2[1-3(y+2)]+y=0

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Solution for 2[1-3(y+2)]+y=0 equation:


Simplifying
2[1 + -3(y + 2)] + y = 0

Reorder the terms:
2[1 + -3(2 + y)] + y = 0
2[1 + (2 * -3 + y * -3)] + y = 0
2[1 + (-6 + -3y)] + y = 0

Combine like terms: 1 + -6 = -5
2[-5 + -3y] + y = 0
[-5 * 2 + -3y * 2] + y = 0
[-10 + -6y] + y = 0

Combine like terms: -6y + y = -5y
-10 + -5y = 0

Solving
-10 + -5y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + -5y = 0 + 10

Combine like terms: -10 + 10 = 0
0 + -5y = 0 + 10
-5y = 0 + 10

Combine like terms: 0 + 10 = 10
-5y = 10

Divide each side by '-5'.
y = -2

Simplifying
y = -2

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